Answer 18.2a
From Mechanics
(Difference between revisions)
(New page: <math>v=10t-6,\quad a=10\ \text{m}{{\text{s}}^{-2}}</math>) |
(New page: <math>v=10t-6,\quad a=10\ \text{m}{{\text{s}}^{-2}}</math>) |
Current revision
\displaystyle v=10t-6,\quad a=10\ \text{m}{{\text{s}}^{-2}}
