Answer 17.9a
From Mechanics
(Difference between revisions)
(New page: <math>15 \textrm{.}3\text{ m}{{\text{s}}^{\text{-1}}}</math>) |
(New page: <math>15 \textrm{.}3\text{ m}{{\text{s}}^{\text{-1}}}</math>) |
Current revision
\displaystyle 15 \textrm{.}3\text{ m}{{\text{s}}^{\text{-1}}}
