Answer 17.6b
From Mechanics
(Difference between revisions)
(New page: <math>4\textrm{.}58\ \text{ m}{{\text{s}}^{-1}}</math>) |
(New page: <math>4\textrm{.}58\ \text{ m}{{\text{s}}^{-1}}</math>) |
Current revision
\displaystyle 4\textrm{.}58\ \text{ m}{{\text{s}}^{-1}}
