Solution 17.3b
From Mechanics
(Difference between revisions)
(New page: <math>KE=\frac{1}{2}\times 0\textrm{.}125\times {{4}^{2}}=1\text{ J}</math>) |
(New page: <math>KE=\frac{1}{2}\times 0\textrm{.}125\times {{4}^{2}}=1\text{ J}</math>) |
Current revision
\displaystyle KE=\frac{1}{2}\times 0\textrm{.}125\times {{4}^{2}}=1\text{ J}
