Solution 17.3a
From Mechanics
(Difference between revisions)
(New page: <math>KE=\frac{1}{2}\times 0\textrm{.}125\times {{12}^{2}}=9\text{ J}</math>) |
(New page: <math>KE=\frac{1}{2}\times 0\textrm{.}125\times {{12}^{2}}=9\text{ J}</math>) |
Current revision
\displaystyle KE=\frac{1}{2}\times 0\textrm{.}125\times {{12}^{2}}=9\text{ J}
