Answer 16.9

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(New page: <math>U=-6\ \text{ m}{{\text{s}}^{-1}},\ V=-12\ \text{ m}{{\text{s}}^{-1}}</math>)
Current revision (17:16, 29 September 2010) (edit) (undo)
(New page: <math>U=-6\ \text{ m}{{\text{s}}^{-1}},\ V=-12\ \text{ m}{{\text{s}}^{-1}}</math>)
 

Current revision

\displaystyle U=-6\ \text{ m}{{\text{s}}^{-1}},\ V=-12\ \text{ m}{{\text{s}}^{-1}}