Solution 16.5
From Mechanics
(Difference between revisions)
			  			                                                      
		          
			|  (New page: Using  <math>{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}</math>  Assume the 2 kg particle is moving in the positive direction,  <math>\begin{align} & 2\time...) | |||
| Line 7: | Line 7: | ||
| <math>\begin{align} | <math>\begin{align} | ||
| & 2\times 5+3\times (-6)=2\times (-2)+3v \\  | & 2\times 5+3\times (-6)=2\times (-2)+3v \\  | ||
| - | & 10- | + | & 10-18=-4+3v \\  | 
| - | &  | + | & -4=3v \\  | 
| - | & v=\frac{ | + | & v=\frac{-4}{3}\text{ m}{{\text{s}}^{\text{-1}}} \\  | 
| \end{align}</math> | \end{align}</math> | ||
| - | The 3 kg particle moves in the  | + | The 3 kg particle moves in the same direction to its original velocity. | 
Current revision
Using
\displaystyle {{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}
Assume the 2 kg particle is moving in the positive direction,
\displaystyle \begin{align} & 2\times 5+3\times (-6)=2\times (-2)+3v \\ & 10-18=-4+3v \\ & -4=3v \\ & v=\frac{-4}{3}\text{ m}{{\text{s}}^{\text{-1}}} \\ \end{align}
The 3 kg particle moves in the same direction to its original velocity.
 
		  