Answer 15.9

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(New page: a) <math>k=2\sqrt{5}</math> b) <math>153\textrm{.}4{}^\circ </math>)
Current revision (14:07, 17 September 2010) (edit) (undo)
(New page: a) <math>k=2\sqrt{5}</math> b) <math>153\textrm{.}4{}^\circ </math>)
 

Current revision

a) \displaystyle k=2\sqrt{5}

b) \displaystyle 153\textrm{.}4{}^\circ