Solution 14.4b
From Mechanics
(Difference between revisions)
(New page: In this case the reaction at the left hand support will be zero. Taking moments about the right hand support: <math>\begin{align} & 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm...) |
(New page: In this case the reaction at the left hand support will be zero. Taking moments about the right hand support: <math>\begin{align} & 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm...) |
Current revision
In this case the reaction at the left hand support will be zero. Taking moments about the right hand support:
\displaystyle \begin{align}
& 1\times 18\times 9\textrm{.}8=2\times m\times 9\textrm{.}8 \\
& m=\frac{1\times 18\times 9\textrm{.}8}{2\times 9\textrm{.}8}=9\text{ kg} \\
\end{align}