Solution 14.2

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(New page: Taking moments about the edge of the quay gives: <math>\begin{align} & 1\times 60\times 9\textrm{.}8=1\textrm{.}5\times m\times 9\textrm{.}8 \\ & m=\frac{60}{1\textrm{.}5}=40\text{ kg} \...)
Current revision (19:19, 1 September 2010) (edit) (undo)
(New page: Taking moments about the edge of the quay gives: <math>\begin{align} & 1\times 60\times 9\textrm{.}8=1\textrm{.}5\times m\times 9\textrm{.}8 \\ & m=\frac{60}{1\textrm{.}5}=40\text{ kg} \...)
 

Current revision

Taking moments about the edge of the quay gives:

\displaystyle \begin{align} & 1\times 60\times 9\textrm{.}8=1\textrm{.}5\times m\times 9\textrm{.}8 \\ & m=\frac{60}{1\textrm{.}5}=40\text{ kg} \\ \end{align}