Solution 10.4
From Mechanics
(Difference between revisions)
(New page: We first calculate the particle´s acceleration using Newton´s Second Law <math>F=ma</math>. <math>\begin{align} & 15=6a \\ & \text{giving} \\ & a=2\textrm{.}5\ \text{m}{{\text{s}}^{-...) |
(New page: We first calculate the particle´s acceleration using Newton´s Second Law <math>F=ma</math>. <math>\begin{align} & 15=6a \\ & \text{giving} \\ & a=2\textrm{.}5\ \text{m}{{\text{s}}^{-...) |
Current revision
We first calculate the particle´s acceleration using Newton´s Second Law \displaystyle F=ma.
\displaystyle \begin{align}
& 15=6a \\
& \text{giving} \\
& a=2\textrm{.}5\ \text{m}{{\text{s}}^{-2}} \\
\end{align}
Now using the kinematic equation (see section 6),
\displaystyle v=u+at\ gives
\displaystyle \begin{align} & 10=0+2\textrm{.}5\times t \\ & \\ & t=4\ \text{s} \\ \end{align}