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Revision as of 10:03, 20 May 2010 (edit) Ian (Talk | contribs) (New page: Image:10.1b.gif Here <math>T</math> is the tension in the cable and <math>a</math> is the acceleration of the packet. Applying Newton's second law <math>\begin{align} & \uparrow :\ ...) ← Previous diff		Revision as of 10:25, 20 May 2010 (edit) (undo) Ian (Talk | contribs) Next diff →
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	<math>\begin{align}		<math>\begin{align}
-	& \uparrow :\ \text{Resultant}\ \text{Force}=T-300\times 9 \textrm{.}81=	+	& \downarrow :\ \text{Resultant}\ \text{Force}=300\times 9 \textrm{.}81-T=
-	mg = 300\times 0 \textrm{.}1 \\	+	ma = 300\times 0 \textrm{.}1 \\
	& \\		& \\
-	& T=30+2943\approx 2970\ \text{N} \\	+	& T=2943-30\approx 2910\ \text{N} \\
	\end{align}</math>		\end{align}</math>

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Revision as of 10:25, 20 May 2010

Here \displaystyle T is the tension in the cable and \displaystyle a is the acceleration of the packet.

Applying Newton's second law

\displaystyle \begin{align} & \downarrow :\ \text{Resultant}\ \text{Force}=300\times 9 \textrm{.}81-T= ma = 300\times 0 \textrm{.}1 \\ & \\ & T=2943-30\approx 2910\ \text{N} \\ \end{align}