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Revision as of 16:09, 16 May 2010 (edit) Ian (Talk | contribs) (New page: Image:9.1.gif As the parachutist is falling vertically (in other words in a straight line) and at constant speed, her velocity is constant. This means the forces acting on her must ha...) ← Previous diff

Current revision (16:09, 16 May 2010) (edit) (undo) Ian (Talk | contribs) (New page: Image:9.1.gif As the parachutist is falling vertically (in other words in a straight line) and at constant speed, her velocity is constant. This means the forces acting on her must ha...)

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Current revision

As the parachutist is falling vertically (in other words in a straight line) and at constant speed, her velocity is constant. This means the forces acting on her must have zero sum.

Taking upwards as positive,

\displaystyle \uparrow :\quad F-mg=0

\displaystyle F=mg=80\times 9\textrm{.}8=784\ \text{N}