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Revision as of 11:42, 18 April 2010 (edit) Ian (Talk | contribs) (New page: We use the expression for the position vector obtained in part a), <math> \mathbf{r}=(8\mathbf{i}+10\mathbf{j})t+\frac{1}{2}(-10\mathbf{j}){{t}^{\ 2}} </math> From part a) the ball hits t...) ← Previous diff		Current revision (11:45, 18 April 2010) (edit) (undo) Ian (Talk | contribs)
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	From part a) the ball hits the ground when <math>t=2\text{ s}</math>.		From part a) the ball hits the ground when <math>t=2\text{ s}</math>.
-	The distance along the ground is the <math>\mathbf{i}</math> component giving <math>16\text{ m}</math>	+	The distance along the ground is the <math>\mathbf{i}</math> component at this time giving,
		+
		+	<math>16\text{ m}</math>

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Current revision

We use the expression for the position vector obtained in part a), \displaystyle \mathbf{r}=(8\mathbf{i}+10\mathbf{j})t+\frac{1}{2}(-10\mathbf{j}){{t}^{\ 2}}

From part a) the ball hits the ground when \displaystyle t=2\text{ s}.

The distance along the ground is the \displaystyle \mathbf{i} component at this time giving,

\displaystyle 16\text{ m}