Solution 8.4a

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Using <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ \</math> at <math>\ \ t=10</math> gives
Using <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ \</math> at <math>\ \ t=10</math> gives
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<math>\mathbf{v}=4\mathbf{i}– 8\mathbf{j}+(0.2\mathbf{i}+0.3\mathbf{j})\times 10\ \</math> or
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<math>\mathbf{v}=6\mathbf{i}– 5\mathbf{j}</math>

Revision as of 15:57, 13 April 2010

Here we have \displaystyle \mathbf{a}=0.2\mathbf{i}+0.3\mathbf{j},\ \ \displaystyle \mathbf{u}=4\mathbf{i}– 8\mathbf{j}\ \ and \displaystyle \ \ \mathbf{ r}_{0}=6\mathbf{i}+2\mathbf{j}.

Using \displaystyle \mathbf{v}=\mathbf{u}+\mathbf{a}t\ \ at \displaystyle \ \ t=10 gives

\displaystyle \mathbf{v}=4\mathbf{i}– 8\mathbf{j}+(0.2\mathbf{i}+0.3\mathbf{j})\times 10\ \ or

\displaystyle \mathbf{v}=6\mathbf{i}– 5\mathbf{j}



Using \displaystyle \mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+{{\mathbf{r}}_{0}}

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