Solution 3.9b

From Mechanics

(Difference between revisions)
Jump to: navigation, search
(New page: Image:3.9b.gif Friction will "try" and prevent motion that is achieve equilibrium. <math>\begin{align} & \text{For}\ \text{equilibrium}\ P-F=0 \\ & \text{that}\ \text{is}\ F=760\ \...)
Current revision (11:30, 27 March 2011) (edit) (undo)
 
(One intermediate revision not shown.)
Line 1: Line 1:
-
[[Image:3.9b.gif]]
+
[[Image:3.9bNew.gif]]
Friction will "try" and prevent motion that is achieve equilibrium.
Friction will "try" and prevent motion that is achieve equilibrium.
Line 11: Line 11:
Also the maximum friction possible is
Also the maximum friction possible is
-
<math>\mu R=0.4\times 1960=784\ \text{N}</math>.
+
<math>\mu R=0\textrm{.}4\times 1960=784\ \text{N}</math>.
<math>F=760\ \text{N}</math>
<math>F=760\ \text{N}</math>
falls inside this maximum value and thus is the value of the friction.
falls inside this maximum value and thus is the value of the friction.

Current revision

Image:3.9bNew.gif

Friction will "try" and prevent motion that is achieve equilibrium.


\displaystyle \begin{align} & \text{For}\ \text{equilibrium}\ P-F=0 \\ & \text{that}\ \text{is}\ F=760\ \text{N} \\ \end{align}


Also the maximum friction possible is \displaystyle \mu R=0\textrm{.}4\times 1960=784\ \text{N}.


\displaystyle F=760\ \text{N} falls inside this maximum value and thus is the value of the friction.