Solution 3.3

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(New page: Image:2.1.gif First consider the lower mass. If <math>T=T1</math> is the tension in the lower string then <math>mg=7\times 9\textrm{.}8=68\textrm{....)
Current revision (17:08, 26 March 2011) (edit) (undo)
 
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First consider the lower mass.
First consider the lower mass.
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If <math>T=T1</math> is the tension in the lower string then
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If <math>T={{T}_{1}}</math> is the tension in the lower string then
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giving
giving
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<math>T1=68\textrm{.}6\ \text{N}</math>
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<math>{{T}_{1}}=68\textrm{.}6\ \text{N}</math>
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If <math>T=T2</math> is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.
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If <math>T={{T}_{2}}</math> is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.
Thus in this case
Thus in this case
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giving
giving
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<math>T2=147\ \text{N}</math>
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<math>{{T}_{2}}=147\ \text{N}</math>

Current revision

Image:2.1.gif

First consider the lower mass.

If \displaystyle T={{T}_{1}} is the tension in the lower string then


\displaystyle mg=7\times 9\textrm{.}8=68\textrm{.}6\ \text{N}


giving \displaystyle {{T}_{1}}=68\textrm{.}6\ \text{N}


If \displaystyle T={{T}_{2}} is the tension in the upper string then the two masses are regarded as one particle with total mass 15 kg.

Thus in this case


\displaystyle mg=15\times 9\textrm{.}8=147\ \text{N}


giving \displaystyle {{T}_{2}}=147\ \text{N}

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