Answer 14.1
From Mechanics
(Difference between revisions)
(New page: a) b) 10 kg) |
|||
| (One intermediate revision not shown.) | |||
| Line 1: | Line 1: | ||
| - | a) | + | a) <math>65 \textrm{.}3 \text{ N}= 65\frac{1}{3}\text{ N}\text{,} \ \ 130 \textrm{.}7 \text{ N}= 130 \frac{\text{2}}{\text{3}}\text{ N}</math> |
| + | |||
b) 10 kg | b) 10 kg | ||
Current revision
a) \displaystyle 65 \textrm{.}3 \text{ N}= 65\frac{1}{3}\text{ N}\text{,} \ \ 130 \textrm{.}7 \text{ N}= 130 \frac{\text{2}}{\text{3}}\text{ N}
b) 10 kg
