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Revision as of 15:50, 11 October 2010 (edit) Ian (Talk | contribs) (New page: Using the expression for <math>v</math> obtained in part a), <math>\begin{align} & s=\int_{0}^{40}{\left( 20-\frac{3{{t}^{2}}}{128} \right)}dt \\ & \\ & =\left[ 20t-\frac{{{t}^{3}}}{12...) ← Previous diff		Current revision (17:40, 27 March 2011) (edit) (undo) Ian (Talk | contribs)
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	<math>\begin{align}		<math>\begin{align}
-	& s=\int_{0}^{40}{\left( 20-\frac{3{{t}^{2}}}{128} \right)}dt \\	+	& s=\int_{0}^{40}{\left( 20-\frac{3{{t}^{2}}}{320} \right)}dt \\
	& \\		& \\
-	& =\left[ 20t-\frac{{{t}^{3}}}{128} \right]_{0}^{40} \\	+	& =\left[ 20t-\frac{{{t}^{3}}}{960} \right]_{0}^{40} \\
	& \\		& \\
-	& =\left( 20\times 40-\frac{{{40}^{3}}}{128} \right)-0 \\	+	& =\left( 20\times 40-\frac{{{40}^{3}}}{960} \right)-0 \\
	& \\		& \\
-	& =300\text{ m}	+	& =733\text{ m}
	\end{align}</math>		\end{align}</math>

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Current revision

Using the expression for \displaystyle v obtained in part a),

\displaystyle \begin{align} & s=\int_{0}^{40}{\left( 20-\frac{3{{t}^{2}}}{320} \right)}dt \\ & \\ & =\left[ 20t-\frac{{{t}^{3}}}{960} \right]_{0}^{40} \\ & \\ & =\left( 20\times 40-\frac{{{40}^{3}}}{960} \right)-0 \\ & \\ & =733\text{ m} \end{align}