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Revision as of 15:29, 4 October 2010 (edit) Ian (Talk | contribs) (New page: Using the result of part b) with <math>a=0</math> gives <math>\begin{align} & 2t-\frac{3{{t}^{2}}}{20}=0 \\ & t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13.3\ \text{s} \\ \end{align}<...) ← Previous diff		Current revision (16:57, 27 March 2011) (edit) (undo) Ian (Talk | contribs)
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	<math>\begin{align}		<math>\begin{align}
-	& 2t-\frac{3{{t}^{2}}}{20}=0 \\	+	& 2t-\frac{{{t}^{2}}}{5}=0 \\
-	& t=0\ \text{s }\ \text{or }\ t=\frac{40}{3}=13.3\ \text{s} \\	+	& \text{which gives } \\
		+	& t=0\ \text{s }\ \text{or }\ t=10\ \text{s} \\
	\end{align}</math>		\end{align}</math>

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Current revision

Using the result of part b) with \displaystyle a=0 gives

\displaystyle \begin{align} & 2t-\frac{{{t}^{2}}}{5}=0 \\ & \text{which gives } \\ & t=0\ \text{s }\ \text{or }\ t=10\ \text{s} \\ \end{align}