Solution 18.1b
From Mechanics
(Difference between revisions)
(New page: <math>a=\frac{dv}{dt}=2t-\frac{3{{t}^{2}}}{20}</math>) |
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| - | <math>a=\frac{dv}{dt}=2t-\frac{ | + | <math>a=\frac{dv}{dt}=2t-\frac{{{t}^{2}}}{5}</math> |
Current revision
\displaystyle a=\frac{dv}{dt}=2t-\frac{{{t}^{2}}}{5}
