Processing Math: Done
Solution 17.7b
From Mechanics
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| + | The kinetic energy of the particle at <math>A</math> is converted to potential energy at <math>B</math>. | ||
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| + | Using the result of part a) | ||
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| + | <math>\begin{align} | ||
| + | & 0\textrm{.}036=0.05\times 9\textrm{.}8\times (0\textrm{.}8-0\textrm{.}8\cos \theta ) \\ | ||
| + | & \cos \theta =0\textrm{.}908 \\ | ||
| + | & \theta =24\textrm{.}7{}^\circ \\ | ||
| + | \end{align}</math> | ||
Current revision
The kinetic energy of the particle at
Using the result of part a)
05
9.8(0.8−0.8cos
)cos=0.908=24.7
