Solution 13.3

From Mechanics

(Difference between revisions)
Jump to: navigation, search
Current revision (13:26, 6 March 2011) (edit) (undo)
 
Line 3: Line 3:
Take moments about the pivoted end of the level, <math>O</math>.
Take moments about the pivoted end of the level, <math>O</math>.
-
<math>1.5\sin {{60}^{\circ }}\times 80=1.5\times 0.866\times 80=103.9\ \text{N}</math>
+
<math>1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}</math>

Current revision

Image:13.3.gif

Take moments about the pivoted end of the level, \displaystyle O.

\displaystyle 1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}