Solution 13.3

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Take moments about the pivoted end of the level, <math>O</math>.
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<math>1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}</math>

Current revision

Image:13.3.gif

Take moments about the pivoted end of the level, \displaystyle O.

\displaystyle 1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}