From Mechanics

Revision as of 12:42, 18 May 2010 (edit) Ian (Talk | contribs) ← Previous diff		Current revision (09:56, 6 March 2011) (edit) (undo) Ian (Talk | contribs)
Line 1:		Line 1:
-	[[Image:9.5.gif]]	+	[[Image:9.5a.gif]]
-	In the figure <math>R1</math> is the air resistance.	+	In the figure <math>F1</math> is the air resistance.
	Resolving up the plane		Resolving up the plane

---

Current revision

In the figure \displaystyle F1 is the air resistance.

Resolving up the plane

\displaystyle \begin{align} & F1+F-mg\sin {{20}^{\circ }}=0 \\ & \\ & F1=mg\sin {{20}^{\circ }}-F=60\times 9\textrm{.}81\times 0\textrm{.}342-F=201\textrm{.}3\ \text{N}-F \\ \end{align}

Resolving perpendicular to the plane upwards

\displaystyle \begin{align} & R-mg\cos {{20}^{\circ }}=0 \\ & \\ & R=mg\cos {{20}^{\circ }}=60\times 9\textrm{.}81\times 0\textrm{.}94=553\ \text{N} \\ \end{align}

Using the friction equation gives

\displaystyle F=\mu R=0\textrm{.}05\times 553=27\textrm{.}65\ \text{N}

Substituting in the above equation for \displaystyle R1 gives

\displaystyle F1=201\textrm{.}3-27\textrm{.}65\approx 173\ \text{N}