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Solution 8.4a

From Mechanics

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Current revision (12:17, 27 March 2011) (edit) (undo)
 
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The speed is the magnitude of this velocity vector.
The speed is the magnitude of this velocity vector.
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<math>v=\sqrt{{{6}^{2}}+{{\left( -5 \right)}^{2}}}=\sqrt{61}=7\textrm{.}8\ \text{m}{{\text{s}}^{-1}}</math>
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<math>v=\sqrt{{{6}^{2}}+{{\left( -5 \right)}^{2}}}=\sqrt{61}=7\textrm{.}81\ \text{m}{{\text{s}}^{-1}}</math>

Current revision

Here we have a=0.2i+0.3j   u=4i–8j   and   r0=6i+2j.

Using v=u+at   at   t=10 gives

v=4i–8j+(0.2i+0.3j)10   or

v=6i–5j  ms−1

The speed is the magnitude of this velocity vector.

v=62+−52=61=7.81 ms−1 

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