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Revision as of 15:54, 2 April 2010 (edit) Ian (Talk | contribs) (New page: Resolving vertically <math>\begin{align} & {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\ & \\ & {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\ \end{ali...) ← Previous diff		Current revision (16:01, 2 April 2010) (edit) (undo) Ian (Talk | contribs)
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-	Resolving vertically	+	Resolving vertically upwards

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Current revision

Resolving vertically upwards

\displaystyle \begin{align} & {{T}_{1}}\cos {{50}^{\circ }}-mg=0 \\ & \\ & {{T}_{1}}=\frac{mg}{\cos {{50}^{\circ }}}=\frac{490}{0\textrm{.}643}=762\ \text{N} \\ \end{align}