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Revision as of 16:20, 1 April 2010 (edit) Ian (Talk | contribs) (New page: The forces on the particle are in equilibrium as the particle is at rest. The sum of the forces in the normal direction (resolving in the normal direction) <math>\begin{align} & N-mg\co...) ← Previous diff		Current revision (15:32, 2 April 2010) (edit) (undo) Ian (Talk | contribs)
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	<math>\begin{align}		<math>\begin{align}
-	& N-mg\cos {{20}^{\circ }}=0 \\	+	& R-mg\cos {{20}^{\circ }}=0 \\
	& \\		& \\
-	& N=mg\cos {{20}^{\circ }}=20\times 9\textrm{.}8\times 0\textrm{.}94=184\ \text{N} \\	+	& R=mg\cos {{20}^{\circ }}=20\times 9\textrm{.}8\times 0\textrm{.}94=184\ \text{N} \\
	\end{align}</math>		\end{align}</math>

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Current revision

The forces on the particle are in equilibrium as the particle is at rest.

The sum of the forces in the normal direction (resolving in the normal direction)

\displaystyle \begin{align} & R-mg\cos {{20}^{\circ }}=0 \\ & \\ & R=mg\cos {{20}^{\circ }}=20\times 9\textrm{.}8\times 0\textrm{.}94=184\ \text{N} \\ \end{align}