Answer 14.1
From Mechanics
(Difference between revisions)
(New page: a) b) 10 kg) |
|||
Line 1: | Line 1: | ||
- | a) | + | a) <math>65\frac{1}{3}\text{ N}\text{, 130}\frac{\text{2}}{\text{3}}\text{ N}</math> |
+ | |||
b) 10 kg | b) 10 kg |
Revision as of 19:18, 9 November 2009
a) \displaystyle 65\frac{1}{3}\text{ N}\text{, 130}\frac{\text{2}}{\text{3}}\text{ N}
b) 10 kg