13. Moments
From Mechanics
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Solution | Solution | ||
- | Force Moment | + | {| width="100%" cellspacing="10px" align="center" |
- | 5N at O | + | |align="left"| Force |
- | <math>5\times 0=0</math> | + | | valign="top"|Moment |
+ | |- | ||
+ | |5N at O | ||
+ | | valign="top"| <math>5\times 0=0</math> | ||
+ | |- | ||
+ | |8 N | ||
+ | |valign="top"| <math>-8\times 1.2=-9.6</math> | ||
+ | |- | ||
- | 8 N | ||
- | <math>-8\times 1.2=-9.6</math> | ||
- | 7 N | ||
- | <math>7\times 0=0</math> | ||
- | 6 N | + | |7 N |
- | <math>-6\times 0.5=-3</math> | + | | valign="top"| <math>7\times 0=0</math> |
+ | |- | ||
+ | |6 N | ||
+ | | valign="top"| <math>-6\times 0.5=-3</math> | ||
+ | |- | ||
+ | |5 N | ||
+ | | valign="top"| <math>5\times 1.2=6</math> | ||
+ | |- | ||
+ | |4 N | ||
+ | | valign="top"| <math>4\times 0.5=2</math> | ||
+ | |- | ||
+ | |Total Moment | ||
+ | | valign="top"| <math>0-9.6+0-3+6+2=-4.6\text{ Nm}</math> | ||
- | + | |} | |
- | + | ||
- | + | ||
- | + | ||
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Revision as of 11:09, 18 September 2009
Theory | Exercises |
Key Points
The moment of the force about the point O is the product of the force and the perpendicular distance to the line of action of the force from O.
\displaystyle \text{Moment }=Fd
\displaystyle \text{Moment }=Fd\sin \theta
Clockwise moments are negative.
Anti-clockwise moments are positive.
Example 13.1
Example 13.2
Example 13.3
For the rectangular lamina shown below, find the total moment of the forces acting, about the corner marked O.
Solution
Force | Moment |
5N at O | \displaystyle 5\times 0=0 |
8 N | \displaystyle -8\times 1.2=-9.6 |
7 N | \displaystyle 7\times 0=0 |
6 N | \displaystyle -6\times 0.5=-3 |
5 N | \displaystyle 5\times 1.2=6 |
4 N | \displaystyle 4\times 0.5=2 |
Total Moment | \displaystyle 0-9.6+0-3+6+2=-4.6\text{ Nm} |