13. Moments

From Mechanics

(Difference between revisions)
Jump to: navigation, search
Current revision (13:08, 27 April 2011) (edit) (undo)
 
(2 intermediate revisions not shown.)
Line 2: Line 2:
{| border="0" cellspacing="0" cellpadding="0" height="30" width="100%"
{| border="0" cellspacing="0" cellpadding="0" height="30" width="100%"
| style="border-bottom:1px solid #797979" width="5px" |  
| style="border-bottom:1px solid #797979" width="5px" |  
-
{{Selected tab|[[13. Moments|Theory]]}}
+
{{Selected tab|[[13. Moments|Theory]]}}
{{Not selected tab|[[13. Exercises|Exercises]]}}
{{Not selected tab|[[13. Exercises|Exercises]]}}
 +
{{Not selected tab|[[13. Video|Video]]}}
| style="border-bottom:1px solid #797979" width="100%"|  
| style="border-bottom:1px solid #797979" width="100%"|  
|}
|}
- 
- 
== '''Key Points''' ==
== '''Key Points''' ==
Line 24: Line 23:
The resultant moment about <math>O</math> is the sum of the moments about <math>O</math>.
The resultant moment about <math>O</math> is the sum of the moments about <math>O</math>.
 +
'''[[Example 13.1]]'''
'''[[Example 13.1]]'''
[[Image:ex13.1whole.GIF]]
[[Image:ex13.1whole.GIF]]
- 
'''[[Example 13.2]]'''
'''[[Example 13.2]]'''
Line 47: Line 46:
| valign="top"|Moment (Nm)
| valign="top"|Moment (Nm)
|-
|-
-
|5N at O
+
|5N at <math>O</math>
| valign="top"| <math>5\times 0=0</math>
| valign="top"| <math>5\times 0=0</math>
|-
|-

Current revision

       Theory          Exercises          Video      

Key Points

The moment of a force about the point \displaystyle O is the product of the force and the perpendicular distance to the line of action of the force from \displaystyle O.

Image:T13.1.GIF \displaystyle \text{Moment }=Fd

Image:T13.2.GIF \displaystyle \text{Moment }=Fd\sin \theta

Clockwise moments are negative.

Anti-clockwise moments are positive.

The resultant moment about \displaystyle O is the sum of the moments about \displaystyle O.


Example 13.1

Image:ex13.1whole.GIF

Example 13.2

Image:ex13.2.GIF


Example 13.3

For the rectangular lamina shown below, find the total moment of the forces acting, about the corner marked O.

Image:ex13.3.GIF

Solution

Force Moment (Nm)
5N at \displaystyle O \displaystyle 5\times 0=0
8 N \displaystyle -8\times 1\textrm{.}2=-9\textrm{.}6
7 N \displaystyle 7\times 0=0
6 N \displaystyle -6\times 0\textrm{.}5=-3
5 N \displaystyle 5\times 1\textrm{.}2=6
4 N \displaystyle 4\times 0\textrm{.}5=2
Total Moment \displaystyle 0-9\textrm{.}6+0-3+6+2=-4\textrm{.}6\text{ Nm}