Answer 18.1b

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(New page: <math>a=2t-\frac{3{{t}^{2}}}{20}</math>)
Current revision (16:53, 27 March 2011) (edit) (undo)
 
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<math>a=2t-\frac{3{{t}^{2}}}{20}</math>
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<math>a=2t-\frac{{{t}^{2}}}{5}</math>

Current revision

\displaystyle a=2t-\frac{{{t}^{2}}}{5}