Answer 18.1a
From Mechanics
(Difference between revisions)
			  			                                                      
		          
			|  (New page: <math>v={{t}^{2}}-\frac{{{t}^{3}}}{20}</math>) | |||
| Line 1: | Line 1: | ||
| - | <math>v={{t}^{2}}-\frac{{{t}^{3}}}{ | + | <math>v={{t}^{2}}-\frac{{{t}^{3}}}{15}</math> | 
Current revision
\displaystyle v={{t}^{2}}-\frac{{{t}^{3}}}{15}
 
		  