Solution 16.5
From Mechanics
(Difference between revisions)
(New page: Using <math>{{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}</math> Assume the 2 kg particle is moving in the positive direction, <math>\begin{align} & 2\time...) |
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<math>\begin{align} | <math>\begin{align} | ||
& 2\times 5+3\times (-6)=2\times (-2)+3v \\ | & 2\times 5+3\times (-6)=2\times (-2)+3v \\ | ||
- | & 10- | + | & 10-18=-4+3v \\ |
- | & | + | & -4=3v \\ |
- | & v=\frac{ | + | & v=\frac{-4}{3}\text{ m}{{\text{s}}^{\text{-1}}} \\ |
\end{align}</math> | \end{align}</math> | ||
- | The 3 kg particle moves in the | + | The 3 kg particle moves in the same direction to its original velocity. |
Current revision
Using
\displaystyle {{m}_{A}}{{v}_{A}}+{{m}_{B}}{{v}_{B}}={{m}_{A}}{{u}_{A}}+{{m}_{B}}{{u}_{B}}
Assume the 2 kg particle is moving in the positive direction,
\displaystyle \begin{align} & 2\times 5+3\times (-6)=2\times (-2)+3v \\ & 10-18=-4+3v \\ & -4=3v \\ & v=\frac{-4}{3}\text{ m}{{\text{s}}^{\text{-1}}} \\ \end{align}
The 3 kg particle moves in the same direction to its original velocity.