Solution 3.9a

From Mechanics

(Difference between revisions)
Jump to: navigation, search
Current revision (11:28, 27 March 2011) (edit) (undo)
 
(One intermediate revision not shown.)
Line 1: Line 1:
-
[[Image:3.9a.gif]]
+
[[Image:3.9aNew.gif]]
<math>\begin{align}
<math>\begin{align}
& \uparrow \ R-mg=0 \\
& \uparrow \ R-mg=0 \\
-
& R=200\times 9.8=1960\ \text{N} \\
+
& R=200\times 9\textrm{.}8=1960\ \text{N} \\
\end{align}</math>
\end{align}</math>

Current revision

Image:3.9aNew.gif


\displaystyle \begin{align} & \uparrow \ R-mg=0 \\ & R=200\times 9\textrm{.}8=1960\ \text{N} \\ \end{align}