Solution 13.3
From Mechanics
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+ | Take moments about the pivoted end of the level, <math>O</math>. | ||
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+ | <math>1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}</math> |
Current revision
Take moments about the pivoted end of the level, \displaystyle O.
\displaystyle 1 \textrm{.}5\sin {{60}^{\circ }}\times 80=1 \textrm{.}5\times 0 \textrm{.}866\times 80=103 \textrm{.}9\ \text{N}