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		+	In the vertical direction the forces on the tank must be in equilibrium.
		+
		+	<math>\uparrow \ -mg+N+5000\cos {{65}^{\circ }}=0</math>
		+
		+	or
		+
		+	<math>\begin{align}
		+	& N=mg-5000\cos {{65}^{\circ }}=500\times 9\textrm{.}8-5000\times 0\textrm{.}423 \\
		+	& =4900-2113=2787\ \text{N} \\
		+	\end{align}</math>

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Current revision

In the vertical direction the forces on the tank must be in equilibrium.

\displaystyle \uparrow \ -mg+N+5000\cos {{65}^{\circ }}=0

or

\displaystyle \begin{align} & N=mg-5000\cos {{65}^{\circ }}=500\times 9\textrm{.}8-5000\times 0\textrm{.}423 \\ & =4900-2113=2787\ \text{N} \\ \end{align}