Solution 4.7b

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Current revision (16:26, 4 February 2011) (edit) (undo)
 
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<math>\begin{align}
<math>\begin{align}
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& \mathbf{FR}=
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& \mathbf{R}=
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& -24\textrm{.}2\mathbf{i}+134\textrm{.}6\mathbf{j} \ \text{N}\\
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& 55\textrm{.}8\mathbf{i}+54\textrm{.}6\mathbf{j} \ \text{N}\\
\end{align}</math>
\end{align}</math>
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The magnitude of this resultant is
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<math>\sqrt{{{\left( 55\textrm{.}8 \right)}^{2}}+{{\left( 54\textrm{.}6 \right)}^{2}}}=78\textrm{.}1\ \text{N}</math>

Current revision

\displaystyle \begin{align} & \mathbf{F}1 = & 86\textrm{.}6\mathbf{i}+50\mathbf{j}\ \text{N}\\ \end{align}

\displaystyle \begin{align} & \mathbf{F}2= & -30\textrm{.}8\mathbf{i}+84\textrm{.}6\mathbf{j} \ \text{N}\\ \end{align}

\displaystyle \begin{align} & \mathbf{F}3= & -80\mathbf{j}\ \text{N}\\ \end{align}

Summing these vectors give their resultant

\displaystyle \begin{align} & \mathbf{R}= & 55\textrm{.}8\mathbf{i}+54\textrm{.}6\mathbf{j} \ \text{N}\\ \end{align}

The magnitude of this resultant is


\displaystyle \sqrt{{{\left( 55\textrm{.}8 \right)}^{2}}+{{\left( 54\textrm{.}6 \right)}^{2}}}=78\textrm{.}1\ \text{N}

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