From Mechanics
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- | | 3 | + | | |
- | | 4 | + | | '''(7 marks)''' |
- | | 5 | + | | |
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| | 2 (a) | | | 2 (a) |
- | | 2 | + | | [[Image:test2ans2.gif]] |
- | | 3 | + | | B1 |
- | | 4 | + | | (1 mark) |
- | | 5 | + | | B1: Correct horizontal forces. |
| + | Ignore any vertical forces. |
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| | 2 (b) | | | 2 (b) |
- | | 2 | + | | <math>P = 900 \text{N}</math> |
- | | 3 | + | | B1 |
- | | 4 | + | | (1 mark) |
- | | 5 | + | | B1: Correct value for <math>P</math>. |
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| | 2 (c) | | | 2 (c) |
- | | 2 | + | | <math>\begin{align} |
- | | 3 | + | & P-900=2000\times 1\textrm{.}2 \\ |
- | | 4 | + | & P=2400+900=3300 \text{N} \\ |
- | | 5 | + | \end{align}</math> |
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| + | | M1 |
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| + | A1 |
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| + | A1 |
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| + | | (1 mark) |
| + | | M1: Three term equation of motion |
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| + | A1: Correct equation |
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| + | A1: Correct <math>P</math>. |
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| | 2 (d) | | | 2 (d) |
- | | 2 | + | | <math>\begin{align} |
- | | 3 | + | & 800-900=2000a \\ |
- | | 4 | + | & a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\ |
- | | 5 | + | \end{align}</math> |
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| + | Car is slowing down |
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| + | | M1 |
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| + | A1 |
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| + | A1 |
| + | |
| + | A1 |
| + | |
| + | | (4 marks) |
| + | | M1: Three term equation of motion |
| + | A1: Correct equation |
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| + | A1: Correct <math>a</math> |
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| + | A1: Correct statement |
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- | | 1 | + | | |
- | | 2 | + | | |
- | | 3 | + | | |
- | | 4| 5 | + | | '''(9 marks)''' |
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| | 3 (a) | | | 3 (a) |
Revision as of 15:00, 19 January 2011
Solutions
1 (a)
| \displaystyle \begin{align}
& 44 \ \textrm{.}1=\frac{1}{2}\times 9 \ \ 8{{t}^{2}} \\
& t=\sqrt{\frac{44 \textrm{.}1}{4 \textrm{.}9}}=3\text{ s} \\
\end{align}
OR
\displaystyle \begin{align}
& s=\frac{1}{2}\times 9 \textrm{.}8\times {{3}^{2}}=44 \textrm{.}1 \\
& \text{AG} \\
& \therefore \text{Hits ground after 3 seconds} \\
\end{align}
| M1
A1
A1
(M1)
(A1)
(A1)
| (3 marks)
| M1: Use of constant acceleration
equation with \displaystyle v=0
A1: Correct equation
A1: Correct \displaystyle s
|
1 (b)
| \displaystyle \begin{align}
& {{v}^{2}}={{0}^{2}}+2\times 9 \textrm{.}8\times 44 \textrm{.}1 \\
& v=\sqrt{864 \textrm{.}36}=29 \ \textrm{.}4\text{ m}{{\text{s}}^{-1}} \\
\end{align}
OR
\displaystyle \begin{align}
& v=0+9 \textrm{.}8\times 3 \\
& v=29 \textrm{.}4 \text{ m}{{\text{s}}^{-1}} \\
\end{align}
| M1
A1
A1
| (3 marks)
| M1: Use of constant acceleration equation with \displaystyle v=0
A1: Correct equation.
A1: Correct \displaystyle v.
|
1 (c)
| Air resistance would slow the ball down.
| B1
| (1 mark)
| B1: Sensible statement about air resistance.
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|
| (7 marks)
|
|
2 (a)
|
| B1
| (1 mark)
| B1: Correct horizontal forces.
Ignore any vertical forces.
|
2 (b)
| \displaystyle P = 900 \text{N}
| B1
| (1 mark)
| B1: Correct value for \displaystyle P.
|
2 (c)
| \displaystyle \begin{align}
& P-900=2000\times 1\textrm{.}2 \\
& P=2400+900=3300 \text{N} \\
\end{align}
| M1
A1
A1
| (1 mark)
| M1: Three term equation of motion
A1: Correct equation
A1: Correct \displaystyle P.
|
2 (d)
| \displaystyle \begin{align}
& 800-900=2000a \\
& a=\frac{-100}{2000}=-0\textrm{.}05 \text{ m}{{\text{s}}^{-2}} \\
\end{align}
Car is slowing down
| M1
A1
A1
A1
| (4 marks)
| M1: Three term equation of motion
A1: Correct equation
A1: Correct \displaystyle a
A1: Correct statement
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|
| (9 marks)
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3 (a)
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3 (b)
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3 (c)
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4 (a)
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4 (b)
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4 (c)
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5 (a)
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5 (b)
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5 (c)
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