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		+	The kinetic energy of the particle at <math>A</math> is converted to potential energy at <math>B</math>.
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		+	Using the result of part a)
		+
		+	<math>\begin{align}
		+	& 0\textrm{.}036=0.05\times 9\textrm{.}8\times (0\textrm{.}8-0\textrm{.}8\cos \theta ) \\
		+	& \cos \theta =0\textrm{.}908 \\
		+	& \theta =24\textrm{.}7{}^\circ \\
		+	\end{align}</math>

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Current revision

The kinetic energy of the particle at \displaystyle A is converted to potential energy at \displaystyle B.

Using the result of part a)

\displaystyle \begin{align} & 0\textrm{.}036=0.05\times 9\textrm{.}8\times (0\textrm{.}8-0\textrm{.}8\cos \theta ) \\ & \cos \theta =0\textrm{.}908 \\ & \theta =24\textrm{.}7{}^\circ \\ \end{align}