Solution 11.4a
From Mechanics
(Difference between revisions)
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<math>\begin{align} | <math>\begin{align} | ||
- | & \uparrow \ T-\textrm{.}8=ma=(5+1)\times 0\textrm{.}2=1\textrm{.}2 \\ | + | & \uparrow \ T-58\textrm{.}8=ma=(5+1)\times 0\textrm{.}2=1\textrm{.}2 \\ |
& \\ | & \\ | ||
& T=58\textrm{.}8+1\textrm{.}2=60\ \text{N} \\ | & T=58\textrm{.}8+1\textrm{.}2=60\ \text{N} \\ | ||
\end{align}</math> | \end{align}</math> |
Current revision
The total weight is
\displaystyle (5+1)g=6\times 9\textrm{.}81=58\textrm{.}8\ \text{N}
Applying the equation of motion with \displaystyle a=0\textrm{.}2\ \text{m}{{\text{s}}^{-2}}
\displaystyle \begin{align}
& \uparrow \ T-58\textrm{.}8=ma=(5+1)\times 0\textrm{.}2=1\textrm{.}2 \\
& \\
& T=58\textrm{.}8+1\textrm{.}2=60\ \text{N} \\
\end{align}