Solution 8.9a
From Mechanics
(Difference between revisions)
m (New page: Here we use the equation <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> with <math>\mathbf{u}=<math>4\mathbf{i}+6\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math> and <math>\mathbf{v}...) |
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<math>\mathbf{u}=<math>4\mathbf{i}+6\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math> and <math>\mathbf{v}=24\mathbf{i}+46\mathbf{j\text{ m}{{\text{s}}^{\text{-1}}}}</math>. | <math>\mathbf{u}=<math>4\mathbf{i}+6\mathbf{j}\text{ m}{{\text{s}}^{\text{-1}}}</math> and <math>\mathbf{v}=24\mathbf{i}+46\mathbf{j\text{ m}{{\text{s}}^{\text{-1}}}}</math>. | ||
- | Also <math>t=20\text{ s}</math> | + | Also <math>t=20\text{ s}</math> whichh gives, |
+ | |||
+ | <math>24\mathbf{i}+46\mathbf{j}=4\mathbf{i}+6\mathbf{j}+\mathbf{a} \times 20</math> | ||
+ | |||
+ | So, | ||
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+ | <math>20\mathbf{a}=20\mathbf{i}+40\mathbf{j}</math> | ||
+ | giving, | ||
+ | |||
+ | <math>\mathbf{a}=\mathbf{i}+2\mathbf{j} \text{ m}{{\text{s}}^{\text{-2}}}</math> |
Revision as of 15:09, 18 April 2010
Here we use the equation \displaystyle \mathbf{v}=\mathbf{u}+\mathbf{a}t with
\displaystyle \mathbf{u}= and \displaystyle \mathbf{v}=24\mathbf{i}+46\mathbf{j\text{ m}{{\text{s}}^{\text{-1}}}}.
Also \displaystyle t=20\text{ s} whichh gives,
\displaystyle 24\mathbf{i}+46\mathbf{j}=4\mathbf{i}+6\mathbf{j}+\mathbf{a} \times 20
So,
\displaystyle 20\mathbf{a}=20\mathbf{i}+40\mathbf{j} giving,
\displaystyle \mathbf{a}=\mathbf{i}+2\mathbf{j} \text{ m}{{\text{s}}^{\text{-2}}}