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Revision as of 19:02, 14 April 2010 (edit) Ian (Talk | contribs) (New page: <math>\mathbf{u}=\mathbf{i}+2\mathbf{j}</math> and <math>\mathbf{v}= 6\mathbf{i}-8\mathbf{j}</math> when <math>t=10</math>. Also <math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> gives, <...) ← Previous diff		Current revision (19:04, 14 April 2010) (edit) (undo) Ian (Talk | contribs)
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	Also		Also
-	<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t</math> gives,	+	<math>\mathbf{v}=\mathbf{u}+\mathbf{a}t\ </math> gives,
	<math>6\mathbf{i}-8\mathbf{j}=\mathbf{i}+2\mathbf{j}+\mathbf{a} \times 10</math>		<math>6\mathbf{i}-8\mathbf{j}=\mathbf{i}+2\mathbf{j}+\mathbf{a} \times 10</math>

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Current revision

\displaystyle \mathbf{u}=\mathbf{i}+2\mathbf{j} and \displaystyle \mathbf{v}= 6\mathbf{i}-8\mathbf{j} when \displaystyle t=10.

Also

\displaystyle \mathbf{v}=\mathbf{u}+\mathbf{a}t\ gives,

\displaystyle 6\mathbf{i}-8\mathbf{j}=\mathbf{i}+2\mathbf{j}+\mathbf{a} \times 10

\displaystyle 10\mathbf{a}=6\mathbf{i}-8\mathbf{j}-\mathbf{i}-2\mathbf{j}=5\mathbf{i}-10\mathbf{j}

\displaystyle \mathbf{a}=0\textrm{.}5\mathbf{i}-\mathbf{j}\ \text{m}{{\text{s}}^{-2}}