Solution 8.1a

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In this case we have
 
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<math>\mathbf{u}=4\mathbf{i}</math>
 
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,
 
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<math>\mathbf{a}=0.9\mathbf{i}+0.7\mathbf{j}</math>
 
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and
 
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<math>{{\mathbf{r}}_{0}}=400\mathbf{i}+350\mathbf{j}</math>.
 
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Substituting these into the equation
 
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<math>\mathbf{r}=\mathbf{u}t+\frac{1}{2}\mathbf{a}{{t}^{\ 2}}+400\mathbf{i}+350\mathbf{j}</math>
 
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gives the position vector of the ball at time <math>10</math> as:
 
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<math>\begin{align}
 
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& \mathbf{r}=(4\mathbf{i})\times 10+\frac{1}{2}(0.9\mathbf{i}+0.7\mathbf{j})\times {{10}^{\ 2}}+400\mathbf{i}+350\mathbf{j} \\
 
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& =40\mathbf{i}+45\mathbf{i}+35\mathbf{j}+400\mathbf{i}+350\mathbf{j} \\ \\
 
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& =485\mathbf{i}+385\mathbf{j} \ \text{m}
 
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\end{align}</math>
 

Revision as of 17:24, 12 April 2010

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