Solution 6.7a

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  • (cur) (last) 16:23, 8 April 2010 Ian (Talk | contribs) (167 bytes) (New page: Using <math>v=u+at\ \</math> gives <math>\begin{align} & 19-6=a\times 20 \\ & \\ & a=\frac{13}{20}=0\textrm{.}65\ \text{m}{{\text{s}}^{-2}} \\ \end{align}</math>)
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