Solution 6.5b

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  • (cur) (last) 15:57, 8 April 2010 Ian (Talk | contribs) (407 bytes) (New page: Using <math>v=u+at\ \</math> gives <math>v=5+0\textrm{.}2\times 5=6\text{ m}{{\text{s}}^{-1}}</math> The distance travelled during this stage using <math>s=ut+\frac{1}{2}a{{t}^{\ 2}}\ \<...)
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