Solution 6.4b

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  • (cur) (last) 10:38, 7 April 2010 Ian (Talk | contribs) (214 bytes) (New page: Using <math>v=u+at\ \</math> gives <math>\begin{align} & 15=5+0\textrm{.}2\times t \\ & \\ \end{align}</math> where we have used the acceleration calculated in part a). This gives <...)
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