Solution 20.4b

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  • (cur) (last) 14:14, 12 October 2010 Ian (Talk | contribs) (503 bytes) (New page: If <math>F=\mu R</math> then the coin can remain on the surface. This is the maximum value that <math>F</math> can take. That is <math>mr{{\omega }^{2}}=\mu R</math>. This gives <math>\...)
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