Solution 19.7d

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  • (cur) (last) 16:34, 11 October 2010 Ian (Talk | contribs) (401 bytes) (New page: Using the result for the position vector <math>\mathbf{r}</math> from part c), <math>\begin{align} & \mathbf{r}(20)=\left( \frac{{{20}^{3}}}{2}-8\times 20+90 \right)\mathbf{i}+\left( \fra...)
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