Solution 19.4b

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  • (cur) (last) 13:48, 11 October 2010 Ian (Talk | contribs) (272 bytes) (New page: Using the result from part a) for the acceleration, <math>\begin{align} & v=\int{a}dt \\ & \\ & =\int{\left( \frac{2t}{5} \right)}dt \\ & \\ & =\frac{{{t}^{2}}}{5}+c \\ & \\ & t=...)
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